Electric binding energy between electron proton

The hydrogen atom has only one proton and one electron. Below is the model of the hydrogen atom:


The spin direction is indicated by the direction of the arrow. The electron and proton have the same spin direction. The distance of the electron and proton, from the center of the electron to the center of the proton, is 2d. Often written as

Let 1 represent electron, 2 represent proton. Then we have the electron electric field equation as:


If


Then


Given that the proton electric field is:


If


Then






Thus the Hydrogen atom electric field is as the following:








We know that the electric field energy density is:




Where
is the first electron's electric field energy density, which is:


And
is the proton's electric field energy density, which is:




From the above
is the Hydrogen atom's electric field binding energy density.
We can get the Hydrogen atom's electric binding energy as the following:



























































































































































X coordinate is the distance between the proton and the electron with a0 as the unit
Y coordinate is the electron proton binding energy with ev as the unit



 


 











 


X coordinate is the distance between proton and electron with a0 as the unit
Y coordinate is the electron proton force with / a0 as the force unit

 


 

 



X coordinate is the distance between proton and electron with a0 as the unit
Y coordinate is the electron proton force differential with as the unit

 


 

 

X coordinate is the distance between proton and electron with a0 as the unit
Y coordinate is the electron proton force 2nd differential with as the unit

 

Hydrogen has only one proton and electron therefore in our hydrogen atom model, it does not get any extra energy. This is most likely to correspond to the near absolute zero temperature state such as solid or liquid state.
When




When hydrogen is heated in its solid or liquid state, it will emit light with all kinds of wavelengths, which corresponds to the hydrogen continuum spectrum.

When the hydrogen is in the thin gas state, and it absorbs enough extra energy with a flame or electric arc, the hydrogen will emit discrete spectrum called the hydrogen atom spectrum. Its ionization energy is


Let us assume that when the hydrogen atom emits discrete spectrum, the electron proton form a one-dimensional harmonic oscillator.  The electron simple harmonic movement is as follows:

Electron proton within the hydrogen atom act like a simple LC circuit:

We represent

as the maximum electric energy

We represent
as the maximum magnetic energy

Current as we know is


Where
is the electron vibration frequency.

Then the total electromagnetic resonance energy will be as the following


Thus we have



Thus we got the electron resonance frequency as


Since we know the characteristic impedance of electron as:

Then let us assume that the electron characteristic impedance is as follows:



In which


Thus


Then we have








Thus we find out that
is the result of electron electromagnetic resonance with the characteristic impedance

With
as the impedance of free space

The EM wave velocity within free space is light speed.
For the instance with EM characteristic impedance Z, their EM wave velocity V will be


The EM wave velocity is inversely proportional to the EM wave impedance.
Thus EM wave velocity inside the hydrogen becomes


In which

Thus












From the above, within the hydrogen atom, the EM velocity is

Additionally, for the static electron, there is no
direction magnetic field, therefore the static electron EM equation becomes:




By assuming that when the electron makes a simple harmonic movement inside the hydrogen atom, the electron
direction magnetic field is:



Then we have the electron electromagnetic moment as follows



























We know the electron electromagnetic field energy as


And we know,


Equating both equations we get the electron capacitor C as


For the electron harmonic oscillator, we have








Where
is the EM wave length,
is the EM wave velocity,
is the EM wave period,


Given that


After substitution we have



is the electron electromagnetic moment,
is the electron electromagnetic resonance wavelength.




Thus we can get the electron resonance vibration moving equation as the following:








For the hydrogen atom, when it is in the thin gas state, and in the environment of flame or electric arc, it will emit a series of concrete spectrum. Its first spectrum series, the Lyman series is given as


Where m is the reduced mass of electron and proton


As we know the electron's electric energy






















When


The ionization energy of the electron escaping from the hydrogen atom can be calculated as:


In the Ionization process, the electron ionization capacitor is:


The hydrogen atom ionization energy can be rewritten as:



For the Z element, the atom has Z electron, according to their ionization energy from large to small, we can number these electron as K electron. When K=1, it relates to the largest ionization energy electron, when K=Z, it relates to the smallest ionization energy electron. Let us take for example, the atomic structure diagram of the element Neon:

Ne-10 electron configuration


Element 1-10 Ionization energy table (ev as energy unit)

 

1s1

1s2

2s1

2s2

2p1

2p2

2p3

2p4

2p5

2p6

Z

K

1

2

3

4

5

6

7

8

9

10

1

H

13.6

 

 

 

 

 

 

 

 

 

2

He

54.42

24.59

 

 

 

 

 

 

 

 

3

Li

122.45

75.64

5.39

 

 

 

 

 

 

 

4

Be

217.72

153.9

18.21

9.32

 

 

 

 

 

 

5

B

340.23

259.38

37.93

25.15

8.3

 

 

 

 

 

6

C

489.99

392.09

64.49

47.89

24.38

11.26

 

 

 

 

7

N

667.05

552.07

97.89

77.47

47.45

29.60

14.53

 

 

 

8

O

871.41

739.29

138.12

113.9

77.41

54.94

35.12

13.62

 

 

9

F

1103.12

953.91

185.19

157.17

114.24

87.14

62.71

34.97

17.42

 

10

Ne

1362.2

1195.83

239.1

207.28

157.93

126.21

97.12

63.45

40.96

21.56


As we know, for the hydrogen atom, when it is in the resonance ionization process, their ionization energy is given as:





In generation, for the Z element, K electron, let us assume that their effective nuclear charge is:




Where


For K=1, the Z element first electron,


For K=Z, the Z element last electron,


Thus we can get Z element, K electron ionization energy as:


Where














Within the Ionization process, the electron electromagnetic energy converted into kinetic energy, electrons escape from the nucleus, the escape speed is proportional to the effective charge of the nuclei.

Thus we can rewrite element 1-10 ionization energy table as value table

 

1s1

1s2

2s1

2s2

2p1

2p2

2p3

2p4

2p5

2p6

Z

K

1

2

3

4

5

6

7

8

9

10

1

H

0

 

 

 

 

 

 

 

 

 

2

He

0

-0.35

 

 

 

 

 

 

 

 

3

Li

0

-0.18

0.37

 

 

 

 

 

 

 

4

Be

0

-0.12

0.42

0.17

 

 

 

 

 

 

5

B

0

-0.09

0.44

0.32

0.22

 

 

 

 

 

6

C

0

-0.07

0.46

0.37

0.33

0.09

 

 

 

 

7

N

0

-0.06

0.46

0.40

0.38

0.26

-0.03

 

 

 

8

O

0

-0.05

0.47

0.42

0.40

0.33

0.2

0

 

 

9

F

0

-0.05

0.47

0.43

0.42

0.37

0.28

0.2

-0.13

 

10

Ne

0

-0.04

0.48

0.44

0.43

0.39

0.33

0.28

0.13

-0.26

Inside the hydrogen atom, we have












For the element Z, K electron, let us assume that the electron energy of the first spectra serial is as follows:


Where





Then the electron energy of the j spectra serial is given as:


When









Can be determined by a specific spectra line wavelength value
For the hydrogen atom, the first spectra serial










Hydrogen first spectra serial

n

Intensity

Wavelength(vacuum)


2

500

1215.674

0.00079492

2

1000

1215.668

0.00078827

3

300

1025.722

0.00210893

4

100

972.5367

0.00395135

5

50

949.743

0.00631632

6

30

937.8034

0.00919858

7

20

930.7482

0.0125948

8

15

926.2256

0.0164982

For the helium atom, the first spectra serial of the first electron is given as






Helium first electron first spectra serial

n

Intensity

Wavelength(vacuum)


2

500 P

303.7858

0.001024

2

1000 P

303.7804

0.000998

3

150 P

256.3177

0.002337

3

300 P

256.3166

0.00232

4

100 c

243.0266

0.004169

5

50 c

237.3307

0.006532

6

30 c

234.3472

0.009417

7

20 c

232.5842

0.012815

8

15 c

231.4541

0.016725

 

For the helium atom, the second spectra serial of the first electron is given as














Helium first electron second spectra serial

n

Intensity

Wavelength(vacuum)


3

15P

 1640.5326

0.000589808

3

25P

 1640.4897

0.000573476

3

180P

 1640.4742

0.000567574

3

25P

 1640.3914

0.000536048

3

7P

 1640.3750

0.000529803

3

50P

 1640.3447

0.000518265

3

120P

 1640.3321

0.000513467

4

50c

 1215.17

0.00105742

4

35

 1215.09

0.00095877

5

30c

 1084.94

0.00160405

6

15c

 1025.27

0.00233436

7

8c

  992.36

0.00319109

8

6c

  972.11

0.00419641

9

5c

  958.70

0.00535842

For the helium atom, the first spectra serial of the second electron is as follows:










Helium second electron first spectra serial

n

Intensity

Wavelength(vacuum)


2

 50 

591.4121  

0.0341709

2

 1000 

584.3339     

-0.0025752

3

 400 

537.0293     

0.0010497

4

 100 

522.186      

0.00485533

5

 50 

515.596      

0.00999475

6

 35 

512.07       

0.0152871

7

 25 

509.97       

0.0217464

8

 20 

508.63       

0.030658

9

 15 

507.71       

0.0399277

10

 10 

507.08       

0.0545745

11

 7 

506.56       

0.0594603

12

 5 

506.31       

0.0990477

13

 4 

505.90       

0.0821738

14

 3 

505.75       

0.119593

15

 2 

505.61       

0.151823

For the Lithium atom, the first spectra serial of the first electron is written as










Lithium first electron first spectra serial

n

Wavelength(vacuum)


2

135.0011661  

0.00109254

2

134.9957610  

0.00103255

3

113.9057091  

0.00239356

3

113.9045690  

0.00235362

4

107.9992230  

0.00422188

4

107.9987906  

0.00419198

5

105.4679379  

0.00657418

5

105.4677267  

0.0065503

6

104.1420509  

0.00944562

6

104.1419318  

0.00942579

7

103.3585830  

0.0128311

7

103.3585091  

0.0128142

8

102.8563652  

0.016725

8

102.8563162

0.0167103

For the Lithium atom, the first spectra serial of the second electron is as the following









Lithium second electron first spectra serial

n

Intensity

Wavelength(vacuum)


2

500 P

303.7858

0.001024

2

1000 P

303.7804

0.000998

3

150 P

256.3177

0.002337

3

300 P

256.3166

0.00232

4

100 c

243.0266

0.004169

5

50 c

237.3307

0.006532

6

30 c

234.3472

0.009417

7

20 c

232.5842

0.012815

8

15 c

231.4541

0.016725